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zheka24 [161]
3 years ago
14

Percent of change from 115 to 338

Mathematics
1 answer:
MrRa [10]3 years ago
7 0

Answer:

237 ⁹/23% change

Step-by-step explanation:

115=100%

337-155=273 which represents the increase

115=100

273=?

273×100÷115= 237 ⁹/23%

Answer =237⁹/23%

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jarptica [38.1K]
Hello : 
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions : 
2x= x +2k</span>π    or x= π -x +2kπ ..... k in : Z
x = 2kπ  or : x = π/2 + kπ 
but :
 <span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are : 
</span>k = 0 : x=0    , x= π/2
k=1 : x=2 π    , x=3π/2
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3 years ago
Which of the following inequalities is represented by the graph?
marusya05 [52]
I believe the answer is b.
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Ray predicted he would score 18 points during a basketball game. He only scored 12 points. What is his percent error
Andre45 [30]

Answer:

hey read this no quema cuh

Step-by-step explanation:

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3 years ago
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Solve the inequality and graph the solution<br> 4x-5&gt;7
ohaa [14]

Answer:

x > 3

interval notation: (3, ∞)

Step-by-step explanation:

Given the inequality statement: 4x - 5 > 7,

The goal is to isolate x and find its solution.

Start by adding 5 to both sides:

4x - 5 + 5 > 7 + 5

4x > 12

Divide both sides by 4:

4x/4 > 12/4

x > 3

The solution can also be expressed in the following interval notation:

(3, ∞).

In terms of graphing, it involves an empty circle on the endpoint, x = 3, as it is not included as a solution. The solution to the given inequality statement must be greater than 3.  

5 0
2 years ago
Find the percent of change from the first value to the second. 72: 81 -
nordsb [41]

Answer:

+12.5%

Step-by-step explanation:

This is rather simple. Subtract 72 from 81, then put the difference over 72. Then, multiply that by 100.

(81 - 72)/72 * 100

<em>Subtract 72 from 81 to get 9</em>

9/72 * 100

<em>Multiply 9 by 100 to get 900</em>

900/72

<em>Simplify the above fraction by cancelling out 9.</em>

100/8

<em>Divide 100 by 8 to get 12.5%</em>

The percent of change is +12.5%

5 0
2 years ago
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