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ikadub [295]
3 years ago
11

I need to find the areathere are 3 rectangles and a trapezoid show how plz

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0
The area of a rectangle is length x width. We can find the 3 areas of the rectangles with this formula:

20 x 5 = 100
100 yd²

15 x (20-14) = 90
90 yd²

14 x 10 = 140
140 yd²

The area of a trapezoid is 1/2(b1+b2)h
In this problem:

b1=25-15-5
b1=5
b2=10
h=20-14
h=6

We can then plug this into the formula:

A = 1/2(5+10)(6)
A = 1/2(15)(6)
A = 45 yd²

We can then get the area of the whole polygon by adding up the areas of the three rectangles and trapezoid:

A = 100+90+140 + 45
A = 375 yd²
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28÷4=7   7×50=350  350×4=1400  

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3 years ago
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Describe the possible lengths of the third side of the triangle given that the lengths of the other two sides are 2 feet and 40
Marrrta [24]

Answer:

The length of the third side is between 16 inches and 64 inches.

Step-by-step explanation:

The length of a side of a triangle is between the sum and the difference of the lengths of the other two sides.

First, we need both sides in the same units. Let's convert feet to inches.

2 ft * (12 in.)/(ft) = 24 in.

The sides measure 24 inches and 40 inches.

Now we add and subtract the two lengths.

40 in. + 24 in. = 64 in.

40 in. - 24 in. = 16 in.

The length of the third side is between 16 inches and 64 inches.

8 0
3 years ago
For the given function f and g, complete parts (a)-(h). For parts (a)-(d), also find the domain.
kakasveta [241]

Answer:

a) (f + g)(x) = 9x + 1

Domain: x ε R

b) (f - g)(x) = (-5x + 13)

Domain: x ε R

c) (f.g)(x) = 14x² + 37x - 42

Domain: x ε R

d) (f/g)(x) = (2x + 7)/(7x -6)

Domain: (x ε R except x = 6/7)

e) (f + g)(7) = 64

f) (f - g)(2) = 3

g) (f.g)(3) = 195

h) (f/g)(x) = 1/3

Step-by-step explanation:

f(x) = 2x + 7, g(x) = 7x - 6

a) (f + g)(x) = f(x) + g(x) = (2x + 7) + (7x - 6)

(f + g)(x) = 9x + 1

Since x is defined for functions f & g for all real numbers, the domain of (f + g)(x) is x ε R

b) (f - g)(x) = f(x) - g(x) = (2x + 7) - (7x - 6)

(f - g)(x) = (-5x + 13)

Since x is defined for functions f & g for all real numbers, the domain of (f - g)(x) is x ε R

c) (f.g)(x) = f(x) × g(x) = (2x + 7)(7x - 6)

(f.g)(x) = 14x² - 12x + 49x - 42 = 14x² + 37x - 42

Since x is defined for functions f & g for all real numbers, the domain of (f.g)(x) is x ε R

d) (f/g)(x) = f(x)/g(x) = (2x + 7)/(7x -6)

x is defined for functions f & g for all real numbers, the domain of (f/g)(x) will be x ε R except when the denominator vanishes (that is, goes to zero). This will cause the function to take up values of ∞.

This will happen when 7x - 6 = 0, x = 6/7.

Therefore, the domain of (f/g)(x) is x ε R except the point, x = 6/7.

e) (f + g)(7) = 9(7) + 1 = 64

f) (f - g)(2) = -5(2) + 13 = 3

g) (f.g)(3) = 14(3²) + 37(3) - 42 = 195

h) (f/g)(27) = (2(27) + 7)/(7(27) - 6) = 61/183 = 1/3

Hope this Helps!!!

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Answer:

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Step-by-step explanation:

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