A set containing
elements has a power set containing
elements; here,
so
.
The elements of the power set are all possible combinations of up to 5 of the total 5 elements to choose from:
0 choices (1):
(since
)
1choice (5):
2 choices (10):
3 choices (10):
and so on
4 choices (5);
and so on
5 choices (1):
(1 + 5 + 10 + 10 + 5 + 1 = 32)
Answer:
Step-by-step explanation:
I THINK IT IS:
C AND MAYBE D?
sorry i had captions on
Step-by-step explanation: x+(x+2)+(x+4)+(x+6)+(x+8)+(x+10)=126
6x+30=126
6x=96
X=16
Since x is the first number , x+6 is the fourth even number .
Thus, the fourth number in the sequence is 22
Answer:
q^12
Step-by-step explanation:
(q^6)^2
using the power of power rule we can multiply the exponents
q^6^2 = q^ (6*2) = q^ 12
The replica is 1/12 of the other noe
so
1/12 of 400=20?
33.333=20?
false
nope
16 is 1/12 of 320?
16=26.666666?
nope
it is not correct dialation
it is bigger tho so it will cover the monument