here's the solution,
- n = 11
- a = 5 ( a = first term )
- d = 6 ( d = common difference )
we know,
=》

=》

=》

=》

=》

nth term ( 11th term ) = 65
If there are 27 students in the class and they have to form as many groups of 4 as possible, you can calculate this using the following step:
27 / 4 = 6.75 = 6 3/4
Result: 27 students can form 6 groups of 4 students and 3 students have to form their own group.
I'm pretty sure the above fractions are equivalent because if you reduce 5s/15t then it equals s/3t.
21 + -12x=0 I think that is the solutiuon