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Strike441 [17]
3 years ago
11

Find an ordered pair , x y that is a solution to the equation 6x+y=9

Mathematics
2 answers:
WARRIOR [948]3 years ago
8 0
6/x 9/y than multiple them then you will get the answer
Marat540 [252]3 years ago
3 0

Answer:

(1, 3 )

Step-by-step explanation:

To find a solution to the equation.

Rearrange making y the subject by subtracting 6x from both sides

Given

6x + y = 9, then

y = 9 - 6x

Substitute any value of x into the equation and solve for y to obtain a solution

x = 1 → y = 9 - 6(1) = 9 - 6 = 3

Thus (1, 3) is a solution to the equation

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What is the value of 14:45?
bazaltina [42]

Answer:

31.111111111111%

Step-by-step explanation:

How much is 14 out of 45 written as a percent value? Convert fraction (ratio) 14 / 45 Answer: 31.111111111111%

3 0
3 years ago
HELP PLS Steven keeps
Archy [21]

Answer:

Option (3)

Step-by-step explanation:

Steven has created a box plot to record the number of students who attended the science club meeting.

In a box plot, initial dot represents the minimum number and extreme point represents the maximum number.

From the graph attached,

Maximum number of students who attended the meeting are 32.

Therefore, Option (3) will be the correct option.

5 0
3 years ago
W=1/9(x+y-z)<br> what’s the answer please help
KatRina [158]

Answer:

1/9x+1/9y-1/9z

Step-by-step explanation:

3 0
4 years ago
Find f f'(x)=1+3sqrt(x) f(4)=25
wlad13 [49]
It appears that you have a derivative and want to integrate...

dy/dx=1+3√x 

y(x)=x+(2/3)x^(3/2)+C  you are given that f(4)=25 so we can solve for the constant of integration...

y(4)=25=4+16/3+C

21=16/3+C

(63-16)/3=C

47/3=C so

f(x)=x+(2/3)x^(3/2)+47/3

f(x)=(3x+2x^(3/2)+47)/3


6 0
3 years ago
What is the quotient (7x^(2))/(2x+6)-:(3x-5)/(x+3)
Irina18 [472]

Answer:

5.525

Step-by-step explanation:

1. (7x^(2))/(2x + 6) -:(3x - 5) / (x + 3) Solve Bold

   (7x^(2)) / (2x + 6) -:(3x - 5) / (x + 3)

2. 49x / 8x - (-2x) / 3x Solve Bold

   49x/8x-(-2x)/3x

3. 6.125 - .6 Solve Bold

Answer: 5.525

5 0
2 years ago
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