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Vaselesa [24]
3 years ago
11

Which expressions are equivalent to (2 Superscript 5 Baseline) Superscript negative 2? 2–10 and StartFraction 1 Over 20 EndFract

ion 2–10 and StartFraction 1 Over 1024 EndFraction 10–2 and StartFraction 1 Over 100 EndFraction 10–10 and StartFraction 1 Over 100 EndFraction
Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

\frac{1}{2^{10}} \ and\ \frac{1}{1024}

Step-by-step explanation:

Given

(2^{5})^{-2}

Required

Find the equivalent;

To find the equivalent of the given expression, we make use of laws of indices;

Using the following law of indices;

(a^m)^n = a^{m*n}

So;

(2^{5})^{-2} becomes

(2^{5})^{-2} = 2^{5*-2}

(2^{5})^{-2} = 2^{-10} ------------ This is one equivalent

Solving further;

Using the following law of indices;

a^{-m} = \frac{1}{a^m}

So;

(2^{5})^{-2} = 2^{-10} becomes

(2^{5})^{-2} = \frac{1}{2^{10}}

2^10 = 1024

Hence;

(2^{5})^{-2} = \frac{1}{1024}

Conclusively; the equivalents of (2^{5})^{-2} are \frac{1}{2^{10}} \ and\ \frac{1}{1024}

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Answer:

314 in²  (nearest whole number)

Step-by-step explanation:

<u>Radius of a regular polygon</u>: The distance from the <u>center</u> of the polygon to any vertex.  The radius of a hexagon is equal to the length of one side.

Therefore, from inspection of the given diagram:

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To find the area of a regular polygon, we first need to calculate the apothem.   The <u>apothem</u> is the line drawn from the center of the polygon to the midpoint of one of its sides.

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Substitute the given values into the formula and solve for a:

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Substitute the given values into the formula and solve for A:

\implies \sf A=\dfrac{6 \cdot 11 \cdot \dfrac{11\sqrt{3}}{2}}{2}

\implies \sf A=314.3672216...

\implies \sf A=314\:\:in^2\:\:(nearest\:whole\:number)

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