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3 years ago

The last question I need help on.

Mathematics

1 answer:

AleksAgata [21]3 years ago

8 0

An ecosystem is a geographic area where plants, animals, and other organisms, as well as weather and landscape, work together to form a bubble of life.

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What is the mean of the normal distribution shown below? -1 0 1 2

Alisiya [41]

Answer:

Should be 1/2, or 0.5

Step-by-step explanation:

The mean is the average, so we divide the sum of the numbers(-1+0+1+2=2) by the quantity(4).

6 0

3 years ago

Read 2 more answers

Solve the problem. Determine which of the following sets is a subspace of Pn for an appropriate value of n. A: All polynomials o

grin007 [14]

Only $A$ and $B$ form subspaces of $P_2$ and $P_4$ , respectively.

$C$ does not form a subspace because it does not contain the zero vector.

3 0

3 years ago

The height of an airplane as it descends to an airport runway

olga55 [171]

Rational. Not whole or integer because its an exact measurement and not irrational because it CAN be expressed as a ratio (fraction, decimal measurement )

4 0

3 years ago

Are all of them correct???

Brilliant_brown [7]

As far as I can see you have gotten the majority of them right.

The only one I see, is the last number on the 4th row from the bottom.

11
x11
------------
121 not 132.

I hope this Helps! :)

4 0

4 years ago

The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas

iren [92.7K]

For the last part, you have to find where $f'(t)$ attains its maximum over $0\le t\le8$ . We have

$f'(t)=-6\sin3t+6\cos2t$

so that

$f''(t)=-18\cos3t-12\sin2t$

with critical points at $t$ such that

$-18\cos3t-12\sin2t=0$

$3\cos3t+2\sin2t=0$

$3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0$

$\cos t(3\cos^2t-9\sin^2t+4\sin t)=0$

$\cos t(12\sin^2t-4\sin t-3)=0$

So either

$\cos t=0\implies t=\dfrac{(2n+1)\pi}2$

$12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi$

where $n$ is any integer. We get 8 solutions over the given interval with $n=0,1,2$ from the first set of solutions, $n=0,1$ from the set of solutions where $\sin t=\dfrac{1+\sqrt{10}}6$ , and $n=1$ from the set of solutions where $\sin t=\dfrac{1-\sqrt{10}}6$ . They are approximately