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docker41 [41]
3 years ago
7

Can someone help? It’s for geometry

Mathematics
2 answers:
Misha Larkins [42]3 years ago
7 0

Answer:

1. Angle GJF

2. Angle ICD

3. Angle ACG

4. 45 degrees

5. Angle ECJ

Maru [420]3 years ago
3 0
What’s your question?
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Use the graph to complete the statement
tamaranim1 [39]

Answer:

C for sure : >

Step-by-step explanation:

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3 years ago
17
xz_007 [3.2K]

Answer:

Center =  \boxed{1}, \: \boxed{ - 2} \: ; \: Radius =  \boxed{3}

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  - 2x + 4y - 4 = 0 \\  \\  ({x}^{2}  - 2x + 1 - 1) + ( {y}^{2}  + 4y + 4 - 4) - 4 = 0 \\  \\ ( {x}^{2}  - 2x + 1) + ( {y}^{2}  + 4y + 4) - 9 = 0 \\  \\  {(x - 1)}^{2}  +  {(y + 2)}^{2}  = 9 \\  \\ {(x - 1)}^{2}  +  {(y + 2)}^{2}  =  {3}^{2}  \\  \\ equating \: it \: with \\  \\  {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}  \\  \\ h = 1 \\ k =  - 2 \\ r = 3 \\  \\ center =  \boxed{1} \: \boxed{ - 2} \:  \: radius =  \boxed{3}

3 0
3 years ago
A machine produces 240 bolts in 25 minutes. At the same rate how many bolts would be produced in 45 minutes
Leni [432]
192 bolts will be produced in 45 minutes
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The formula d = rt. Find how long it takes an airplane to fly 375 at 500 miles per hour
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4 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
  • f(x) ≥ 0 over the interval [2, ).

<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

Since the table with x  and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .

Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

brainly.com/question/14454639

#SPJ1

6 0
2 years ago
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