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olchik [2.2K]
2 years ago
14

Which triangle cannot be used to find the slope of the line?

Mathematics
1 answer:
Llana [10]2 years ago
4 0

Answer:

D

Step-by-step explanation:

It doesn't follow the rise over run rule

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Ken, the camp cook, makes 3 meals for every camper. The
dalvyx [7]

Answer: number of meals on the left side then number of campers on the bottom

Step-by-step explanation:

A p e x and it says 3 meals for every camper it never said how long so it’s not going to be so the graphs with day in it next you can’t put campers on the side cause if you don’t have enough meals for everyone you ant goin keep the campers happy so that’s how I got my answer sorry if that was confusing brainless please

3 0
3 years ago
Read 2 more answers
Help appreciated! (Will mark as Brainliest)
WARRIOR [948]

Answer:

trapezoid

Step-by-step explanation:

parallelograms require two sets of parallel lines while trapezoids do not, only requiring one set. it is possible to get a trapezoid with 2 90 degree angles.

3 0
3 years ago
Identify the zero(s) of the function graphed below
k0ka [10]

Answer:

Step-by-step explanation:

The zeros are the values of x for which y=0.

The zero of this graph is x=1.

8 0
2 years ago
Property taxes are based on an assessed value of $132,000 and the tax rate is 8.5 mills. The property closes on Jun 14. On a bas
defon

Answer:

$132,000 X .0085 = $1,122 / 360 = $3.1166 X 164 = $511.13

One mill is one dollar per $1,000 dollars of assessed value.

In our case 8.5 mills equivalent to 0.0085.

So to get the assessed value for one day

we will get

$132,000 X .0085 = $1,122 / 360 = $3.1166

Now we have the value for one day,

For June 14, we will calculate the days from January 1st to date

total days are 164.  i.e. 5*30+14 = 164

Finally, the seller owes

$3.1166 * 164 = 511.13

6 0
3 years ago
Suppose a research firm conducted a survey to determine the average amount of money steady smokers spend on cigarettes during a
olchik [2.2K]

Answer:

option (b) 0.0228

Step-by-step explanation:

Data provided in the question:

Sample size, n = 100

Sample mean, μ = $20

Standard deviation, s = $5

Confidence interval = between $19 and $21

Now,

Confidence interval = μ ± z\frac{s}{\sqrt n}

thus,

Upper limit of the Confidence interval = μ + z\frac{s}{\sqrt n}

or

$21 =  $20 + z\frac{5}{\sqrt{100}}

or

z = 2

Now,

P(z = 2) = 0.02275                       [From standard z vs p value table]

or

P(z = 2) ≈ 0.0228

Hence,

the correct answer is option (b) 0.0228

3 0
3 years ago
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