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Yanka [14]
3 years ago
11

Find the general solution and find the specific solutions over the interval [0,4pi]

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

Isolate the angle 2x, by following the reverse "order of operations".

Step-by-step explanation:

Explanation:

Step 1: Add 1 to both sides:

2

cos

2

(

2

x

)

=

1

Step 2: Divide both sides by 2:

cos

2

(

2

x

)

=

1

2

Step 3: Take the square root of both sides:

cos

(

2

x

)

=

√

2

2

or

cos

(

2

x

)

=

−

√

2

2

(don't forget the positive and negative solutions!)

Step 4: Use inverse of cosine to find the angles:

2

x

=

cos

−

1

(

√

2

2

)

or

2

x

=

cos

−

1

(

−

√

2

2

)

Step 5: Find angles that work:

2

x

=

π

4

or

2

x

=

7

π

4

or

2

x

=

3

π

4

or

2

x

=

5

π

4

Step 6: Solve for x:

x

=

π

8

,

7

π

8

,

3

π

8

,

5

π

8

or .785, 5.5, 2.36, 3.93

(decimal approximations are seen on the graph below)

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dmitriy555 [2]

Answer:

40%

Step-by-step explanation:

15-9=6

6/15=2/5=40/100=40%

4 0
3 years ago
Read 2 more answers
Ppppppppppllllllllls I need helppppppp​
Phantasy [73]

Answer:

ΔABC≅ΔDEC by AAS

Step-by-step explanation:

You can use the AAS method of congruency.

Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent

Hope this helped.

5 0
3 years ago
Help me please if you can
makvit [3.9K]

Answer:

-2

Step-by-step explanation:

Add them up: -14

Divide by how many there are: -14 / 7 = -2

4 0
3 years ago
In this assignment, you will explore how the volume is changed when you adjust the height or radius of a cylinder. You will drag
lesantik [10]

The volume of a cylinder changes when you adjust the height or radius as the volume either increases or reduces.

<h3>How to illustrate the volume?</h3>

Let's assume that the height and radius are 14cm and 7cm. The volume will be:

= πr²h

= 3.14 × 7² × 14

= 2154.04cm³

When the radius and height are reduced to 5cm and 9cm, the volume will be:

= πr²h

= 3.14 × 5² × 9

= 706.5cm³

This illustrates that the volume reduces when the height and radius reduces.

Learn more about volume on:

brainly.com/question/1972490

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8 0
2 years ago
Before sending track and field athletes to the Olympics, the U.S. Holds a qualifying meet. The box plots below show the distance
sleet_krkn [62]

Question:

The options are;

A. The distances in the Olympic final were farther on average.

B. The distances in the Olympic final varied noticeably more than the US qualifier distances

C. The distances in the Olympic final were all greater than the US qualifier distances

D. none of the above

Answer:

The correct option is;

A. The distances in the Olympic final were farther on average.

Step-by-step explanation:

From the options given, we have

A. The distances in the Olympic final were farther on average.

This is true as the sum of the 5 points divided by 5 is more in the Olympic final

B. The distances in the Olympic final varied noticeably more than the US qualifier distances

This is not correct as the difference between the upper and lower quartile in the Olympic final is lesser than in the qualifier

C. The distances in the Olympic final were all greater than the US qualifier distances

This is not correct as the max of the qualifier is more than the lower quartile in the Olympic final

D. none of the above

We have seen a possible correct option in option A

7 0
3 years ago
Read 2 more answers
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