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irina [24]
3 years ago
8

(8n+1)(6n-3) please solve in quadratic formula

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0
Use the distributive property.

(8n+1)(6n-3)=(8n)(6n)+(8n)(-3)+(1)(6n)+(1)(-3)\\\\=48n^2-24n+6n-3=48n^2-18n-3
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Answer: The first radio button choice  8/3 * m^8


Steps:

120 (m^ 16)  /  45 (m^8) =

120/45  *  (m^16)/(m^8) =

Simplify 120/45  (15 or 5 *3 divides each). Since base "m" is same in both terms simply subtract exponents.

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MrB

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Answer:

The other leg is  12 cm  long.

Step-by-step explanation:

c

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(

15 cm

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2

−

(

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4 0
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6 0
3 years ago
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