Answer & Step-by-step explanation:
Using the information given in the question we can form the following 3 equations (in the order of the first 3 sentences)
w = 2h (twice the price)
t = h - 4 ($4 less)
3w + 2h + 5t = 136 (total purchasing and cost)
We can solve all 3 equations for h first, by substituting the first two equations, into the third equations w and t
3(2h) + 2h + 5(h-4) = 136
Simplify
6h + 2h + 5h - 20 = 136
13h = 136 + 20
13h = 156
h = 156/13
h = $12
Using this information, we can solve for w and t
w = 2h
w = 2(12)
w = $24
And finally
t = h - 4
t = 12 - 4
t = $8
There are 5^5 students on the school and 5^2 students per class.
So, think:
1 class ----------- 5^2 students
x classes ---------- 5^5 students
Multiply:
1 . 5^5 = x . 5^2
So,
5^5 = x.5^2
x = 
x = 
x = 
x = 125
There are 125 classes.
Answer:
4
Step-by-step explanation:
Answer:
y = 4x + 1
Step-by-step explanation:
y = mx + b
b = y-intercept
From the graph we see that b = 1
m = slope
Start at (0, 1). Go up 8 units. Rise = 8. Go right 2 units. Run = 2.
slope = rise/run = 8/2 = 4
y = 4x + 1
51 = 3k. We can switch this around to 3k = 51 (because it's easier for me)
3k = 51.
We divide by 3 on both sides to just get "k".
3k / 3 = 51 / 3
k = 17.
