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blondinia [14]
4 years ago
7

Evaluate 29 • 1 + 2(20 ÷ 4 – 5)

Mathematics
2 answers:
Leno4ka [110]4 years ago
8 0

29..................................

Troyanec [42]4 years ago
4 0

Answer:

29

Step-by-step explanation:

29 x 1 + 2(20 : 4 - 5) = ...

29 + 2(0) = ...

29 + 0 = 29

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Tavon has a gift card for $70 that loses $3 for each​ 30-day period it is not used. He has another gift card for $ 60 that loses
vladimir2022 [97]

Hello,


Your answer would be: 55


<u><em>My work:</em></u>

For this problem all you have to do is keeping subtracting 3 until you get a matching number in which I got 55.


Hope this helps!


Brainliest!?!


Have a great day:)


~Rendorforestmusic

5 0
3 years ago
PLEASE HELP ITSFOR GEOMETRY DO NOT WASTE ANSWERS WILL MARK BRAINLIEST
iris [78.8K]

Answer:

26 miles

Step-by-step explanation:

use pythagorean theorem to find that from post office to stevie's is 10 miles long( 6^2 + 8^2=100, and the square root of 100 is 10) then add the total distence together and get 8+8+10=26

3 0
4 years ago
Find the missing side of this triangle, round to the nearest tenth if needed PLEASE HELP WILL MARK BRAINLIEST
serious [3.7K]

Answer:

The value of x:

  • x\:\approx \:8 in

Step-by-step explanation:

Given

b=4.8 in

c=9.3 in

a = x

we have to determine 'x'.

As the given triangle is a right-angled triangle.

Pythagorean Theorem:

For a right-angled triangle, with sides 'a' and 'b', the hypotenuse 'c' is defined as

c=\sqrt{a^2+b^2}

so

a=\sqrt{c^2-b^2}

as

  • b=4.8 in
  • c=9.3 in
  • a = x

substituting the values

x=\sqrt{9.3^2-4.8^2}

x\:\approx \:8 in

Thus, the value of x:

  • x\:\approx \:8 in
8 0
3 years ago
Hi, can you help to find (all the roots/zeros), please!!!
OLga [1]

Solution

Given the quadratic equation

x^2-2x-38=0

we need to find the zeros of the equation

To do that, we use the completing the square method

Step 1. Add 38 to both sides

\begin{gathered} \Rightarrow x^2-2x-38+38=38 \\  \\ \Rightarrow x^2-2x=38 \end{gathered}

Step 2: add the square of half of the coefficient of x to both sides

That is;

\begin{gathered} \Rightarrow x^2-2x+(\frac{1}{2}\cdot(-2))^2=38+(\frac{1}{2}\cdot(-2))^2 \\  \\ \Rightarrow x^2-2x+1=38+1 \\  \\ \Rightarrow x^2-2x+1=39 \\  \\ \Rightarrow(x-1)^2=39 \end{gathered}

Step 3: Simplify the above expression;

\begin{gathered} \Rightarrow x-1=\pm\sqrt[]{39} \\  \\ \Rightarrow x=1\pm\sqrt[]{39} \end{gathered}

4 0
1 year ago
(x-2)(x+7)
Nookie1986 [14]
So you use x = 2.
x-2 = 0
x+7=9
so (0,9) (x,y)
5 0
3 years ago
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