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3 years ago

PLZ HELP ASAP AND SHOW UR WORK!!!! THE ≤. WITHOUT THE LINE IN THE BOTTOM

Mathematics

1 answer:

Marina86 [1]3 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{2}{3}x +6$

subtract 6 from both sides

$\frac{2}{3}x$

divide by 2/3(or multiply by 3/2)

$x$

and thats your answer

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A solid silver spoon has a mass of 65.1g.

Keith_Richards [23]

Answer:

D=M/V

D=65.1/6.2

Density is 10.5 grams per centimetre cube

Step-by-step explanation:

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3 years ago

Plssss help quick i need it for sum important

Vanyuwa [196]

(a) The product of $(2x-4)\ and\ (3x^2-x+4)$ is calculated to be $=6x^3-14x^2+12x-16$

(b)The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

<u>Step-by-step explanation:</u>

$(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16$

$(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8$

The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

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3 years ago

Bored someone talk to me

Softa [21]

Yo whats up homie ❓❓❓

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3 years ago

Tony can type at a constant rate of 110 words every 2 minutes.

kati45 [8]

Answer:

W = 55T

Step-by-step explanation:

He types 110 / 2 = 55 words every minute. Thus, W = 55T

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3 years ago

Simplify sin q + cosq cotq.

IRINA_888 [86]

$\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}$

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3 years ago