Answer:
C
Step-by-step explanation:
The distributive property says that
![a\cdot (b+c)=a\cdot b+a\cdot c](https://tex.z-dn.net/?f=a%5Ccdot%20%28b%2Bc%29%3Da%5Ccdot%20b%2Ba%5Ccdot%20c)
Consider option C. In this option,
![(0.7\cdot 0.7)+(0.7\cdot 0.9)+(0.7\cdot 0.2)=0.7\cdot (0.7+0.9+0.2)](https://tex.z-dn.net/?f=%280.7%5Ccdot%200.7%29%2B%280.7%5Ccdot%200.9%29%2B%280.7%5Ccdot%200.2%29%3D0.7%5Ccdot%20%280.7%2B0.9%2B0.2%29)
The left part consists of three products
![(0.7\cdot 0.7)\\ (0.7\cdot 0.9)\\ (0.7\cdot 0.2)](https://tex.z-dn.net/?f=%280.7%5Ccdot%200.7%29%5C%5C%20%280.7%5Ccdot%200.9%29%5C%5C%20%280.7%5Ccdot%200.2%29)
Each of these products has the factor
Usig the distributive property, we can write this factor before the brackets and all remaining factors write as the sum in the brackets:
![0.7\cdot (0.7+0.9+0.2)](https://tex.z-dn.net/?f=0.7%5Ccdot%20%280.7%2B0.9%2B0.2%29)
This is exactly the right part of equality from option C.