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vredina [299]
3 years ago
5

Evaluate x2 + 3x ; x = -3

Mathematics
1 answer:
stepladder [879]3 years ago
5 0
The answer would be -15
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The two lines y=2/5x+9 and y= -2/5x-9 are: <br> a) parallel <br> b) perpendicular <br> c)neither
irakobra [83]

Answer:

neither

Step-by-step explanation:

parallel lines have the same slope and different y-intercept

perpendicular lines have the reciprocal as slopes( 2/5 and 5/2)

as these slopes have neither the answer in NEITHER

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Consider the integral 8 (x2+1) dx 0 (a) Estimate the area under the curve using a left-hand sum with n = 4. 250 Is this sum an o
Leya [2.2K]

Answer:

  (a) 120 square units (underestimate)

  (b) 248 square units

Step-by-step explanation:

<u>(a) left sum</u>

See the attachment for a diagram of the areas being summed (in orange). This is the sum of the first 4 table values for f(x), each multiplied by 2 (the width of the rectangle). Quite clearly, the curve is above the rectangle for the entire interval, so the rectangle area underestimates the area under the curve.

  left sum = 2(1 + 5 + 17 + 37) = 2(60) = 120 . . . . square units

<u>(b) right sum</u>

The right sum is the sum of the last 4 table values for f(x), each multiplied by 2 (the width of the rectangle). This sum is ...

  right sum = 2(5 +17 + 37 +65) = 2(124) = 248 . . . . square units

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3 years ago
What is 3/14 divided by 1/2 (Reduce to lowest terms!)
cricket20 [7]
The answer to that question is 3/7
7 0
3 years ago
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Given the graph of log y=log(2)x. Find the area of the three inscribed rectangles
evablogger [386]

Answer: 6+2log_{2} 6

Step-by-step explanation:

S=s_{1} +s_{2} +s_{3} = 2(h_{1} +h_{2} +h_{3} )

h_{1} = log_{2}2=1

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h_{3} = log_{2}6

S = 2(1+2+log_{2}6) = 6+2log_{2}6

8 0
3 years ago
3. If the lateral surface area of a
azamat

Step-by-step explanation:

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2 years ago
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