What is the prefix of wilderness

The percent, X , of shrinkage o n drying for a certain type of plastic clay has an average shrinkage percentage :, where paramet

never [62]

Answer:

a) $t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744$

The degrees of freedom are given by:

$df=n-1=45-1=44$

The critical value for this case is $t_{\alpha}=1.68$ since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

b) $p_v =P(t_{(44)}>2.744)=0.0044$

Step-by-step explanation:

Information given

$\bar X=18.4$ represent the sample mean

$s=2.2$ represent the sample standard deviation

$n=45$ sample size

$\mu_o =17.5$ represent the value to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Part a

We want to test if the true mean is higher than 17.5, the system of hypothesis would be:

Null hypothesis: $\mu \leq 17.5$

Alternative hypothesis: $\mu > 17.5$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing we got:

$t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744$

The degrees of freedom are given by:

$df=n-1=45-1=44$

The critical value for this case is $t_{\alpha}=1.68$ since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

Part b

The p value would be given by:

$p_v =P(t_{(44)}>2.744)=0.0044$

5 0

4 years ago

Thang decided to borrow $9000 from his local bank to help pay for a car. His loan was for 3 years at a simple interest rate of

Virty [35]

$1620

calculate simple interest ( I) using I = PRT

where P is the amount borrowed, R is rate of interest and T is time in years

note that R = 6% = $\frac{6}{100}$ = 0.06

I = $9000 × 0.06 × 3 = $1620

8 0

3 years ago

Gabrielle wants to use felt

Shkiper50 [21]

Answer:

3 pieces

Step-by-step explanation:

Given: Figure

To find: Number of 8.5 in. × 11 in. pieces used to cover the floors of a room and a hallway in her dollhouse

Solution:

In the given figure, AC = 22 in.

AB + BC = 22 in.

AB + EF = 22 (As BC = EF being opposite sides of rectangle)

AB + 10 = 22

AB = 22 - 10 = 12 in.

Area of rectangle ABGH = AB × AH = 12 × 5 = 60 square inches

(area of rectangle = length × breadth )

CE = CD + DE = AH + GF (As CD = AH and DE = GF)

CE = 5 + 15 = 20 inches

Area of rectangle BCEF = BC × CE = 10 × 20 = 200 square inches

(BC = EF = 10 in.)

Total area of the figure = Area of rectangle ABGH + Area of rectangle BCEF = 60 + 200 = 260 square inches

Area of pieces of felt = 8.5 × 11

So,

Number of pieces required = Total area of the figure / Area of pieces of felt = $\frac{260}{8.5(11)} =2.78$ $\approx$ 3 pieces

3 0

3 years ago

Lester deposits $80 into a new savings account. The account earns 6.5% simple interest per year. No money is added or removed fr

Sedaia [141]

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$80\\ r=rate\to 6.5\%\to \frac{6.5}{100}\dotfill &0.065\\ t=years\dotfill &3 \end{cases} \\\\\\ A=80[1+(0.065)(3)]\implies A=80(1.195)\implies A=95.6$

4 0

2 years ago

Anyone knows watch estimate means?

Mrac [35]

Basically it means judging if something is right.

3 0

3 years ago

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