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ANTONII [103]
3 years ago
11

Find the area of A circle whose diameter is 8.3m round to the nearest tenth

Mathematics
1 answer:
koban [17]3 years ago
6 0
D=8.3

8.3/2 = 4.15


R=4.15



4.15* 4.15 * 3.14 = 54.07
HOPE THIS HELPS
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Use the quadratic formula to find the solutions to the equation x^2-3x+1=0
Gnom [1K]

Answer:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

Step-by-step explanation:

Using:

x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}

we will have two solutions.

x^2-3x+1=0

So, a=1   b=-3  c=1

x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}

We have two solutions:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

4 0
3 years ago
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laiz [17]

Answer:

The equation in standard form that models area of pumpkins is:

A_p = A_G - A_c

and the area is: x^2+8x+2

Step-by-step explanation:

Given that the garden has corn and pumpkins

The expressions are:

Total area of garden: A_G = 2x^2+5x+4

Area of Corn: A_c = x^2-3x+2

Area of Pumpkins: A_p = ?

The sum of areas of corn and pumpkins is the total area of the garden.

It can be expressed mathematically as:

A_G = A_c+A_p

If we have to find the area of pumpkins,

A_p = A_G - A_c

Putting the values

A_p = (2x^2+5x+4) - (x^2-3x+2)\\A_p = 2x^2+5x+4-x^2+3x-2\\A_p = 2x^2-x^2+5x+3x+4-2\\A_p = x^2+8x+2

The equation in standard form that models area of pumpkins is:

A_p = A_G - A_c

and the area is: x^2+8x+2

3 0
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Wewaii [24]

Answer:

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3 0
2 years ago
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azamat
Answer: C.

Explanation: A function only has one y value for every x value. This means that an x cannot have more than one y value. You can do the vertical line test on graphs to figure out if it is a function or not. In this case, graph C is the only one that passes the vertical line test.
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300 is 10 times as much as
Nonamiya [84]
300 / 10 = 30, because 10*30=300
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3 years ago
Read 2 more answers
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