It would be 2 because 2 divide 2 is 1
A) x – 7 = -7(6y + 5)
x – 7 = -42y + -35
x – 7 + 35 = -42y
x + 28 = -42y
y = (1/42)x – 14/21
c) y – 7 = 7(x + 5)
y – 7 = 7x + 35
y = 7x + 42
b) y – 7 = -7(x + 5)
y – 7 = -7x -35
y = -7x – 28
d) y + 7 = 7(x + 5)
y + 7 = 7x + 35
y = 7x + 28
Answer:
Therefore, the triangles ABD and CDB are congruent by SAS postulate, NOT SSS postulate, which would require 3 pairs of congruent sides.
Answer:2.Triangles ABD and CDB are congruent by the SAS postulate.
Step-by-step explanation:
"Side AB is parallel to side DC so the alternate interior angles, angle ABD and angle CDB, are congruent." is perfectly correct.
"Side AB is equal to side DC and DB is the side common to triangles ABD and BCD." this is also true
so by now we have 2 triangles, with 2 congruent sides, and the angles between these pairs of congruent sides, are also congruent
Sine=opposite/hypotenuse
Cosine=adjacent/hypotenuse
Tangent=opposite/adjacent
sinA=16/20=4/5
cosA=12/20=3/5
tanA=16/12=4/3
