Answer: z = 
<u>Step-by-step explanation:</u>
67a(t + z) = 45z + 67
67at + 67az = 45z + 67
<u>-67at -45z </u> <u>-45z -67at </u>
67az - 45z = 67 - 67at
z(67a - 45) = 67 - 67at
<u>÷ (67a - 45) </u> <u>÷ (67a - 45) </u>
z = 
=
Answer:
23.21
Step-by-step explanation:
The answer you have given is correct.
-12n+12m that is the answer
(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
This construction demonstrate that the set of points equidistance from the endpoints of a line segment is the perpendicular bisector of the segment
