Answer:
The answer to your question is car 1 = 30 gal and car 1 = 20 gal
Step-by-step explanation:
car 1 = a
car 2 = b
Efficiency of car 1 = 35 mi/gal
Efficiency for car 2 = 20 mi/gal
Total distance = 1450
Total gas consumption = 50 gal
Equations
35a + 20b = 1450 ------- (I)
a + b = 50 ------- (II)
Solve by elimination
Multiply equation II by -35
35a + 20b = 1450
-35a - 35b = -1750
Simplify
0 - 15b = -300
Solve for b
b = -300/-15
Result
b = 20
Substitute b in equation II to find a
a + 20 = 50
Solve for a
a = 50 -20
Result
a = 30
Pennies (P) = 24
Nickels = 1/2P
Dimes = 1/2P + 5
Quarters = (1/2P + 5) -6
Therefore...
Nickels = 1/2P = 1/2(24)= 12
Dimes = 12 + 5 = 17
Quarters = 17 - 6 = 11
<u>Top row - Left Row :</u>
Order : Left to Right
{11.7 - below(negative)} , {11.6 - below(negative)} , {12 - exactly filled} , {12.2 - above(positive)}
<u>Middle Row </u>:
Order : Left to Right
{11.1 - below(negative)} , {11.2 - below(negative)} , {11.9 - below(negative)} , {12.5 - above(positive)}
<u>Right Row </u>:
Order : Left to Right
{12 - exactly filled} , {11.4 - below(negative)} , {11.5 - below(negative)} , {10.8 - below(negative)}
ANSWER = 154^3+10^2+12+15
Solve (2x - 1)(3x^2 - 9x - 4)
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