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Afina-wow [57]
3 years ago
11

Reduce to simplest form.

Mathematics
1 answer:
BigorU [14]3 years ago
8 0
Convert 3 6/2 to an improper fraction so: 12/2
convert 2 4/5 to 14/5 
multiply the numerators of the improper fractions so 12*14, which is 168.
multiple the denominators so 2*5, which is 10.
the new fraction is 168/10, so you divide 168 divided by 10, which is 16.8, or 16 4/5.
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A rectangular container can hold 45 candles, while a cylindrical container holds 41 candles. Each rectangular
kap26 [50]

Answer:

  a) no

  b) 143 rectangular containers

  c) 157 cylindrical containers

  d) both (preferring rectangular for the bulk of an order)

Step-by-step explanation:

a) If the company needs to package 6,400 candles, should it use only rectangular or only cylindrical containers to minimize costs?

  No.*

For packaging 41 candles or fewer, the cylindrical container costs less than the rectangular one.

For packaging 6400 candles, there will be 10 candles left over if rectangular containers are used for most of the packaging needs. A dollar can be saved by packaging these remaining candles in a cylindrical container.

__

b) How many rectangular containers will be necessary to package 6,400 candles?

  6400/45 = 142 10/45

If rectangular containers are used for all, then 143 are needed.

__

c) How many cylindrical containers will be necessary to package 6,400 candles?

  6400/41 = 156 4/41

If cylindrical containers are used for all, the 157 are needed.

__

d) Which container should the company use to minimize costs?

  The cost of 143 rectangular containers is 143×$16 = $2288

  The cost of 157 cylindrical containers is 157×$15 = $2355

  The cost of 142 rectangular and 1 cylindrical container is $2287

If only one shape container is used, the company should use rectangular containers to minimize cost. If either shape can be used, cost will be minimized by using one cylindrical container for the remnant of the order.

_____

* This question is directed solely at the cost of materials required for packaging. We have advocated that both rectangular and cylindrical containers be made available. As a practical matter, the cost to the company of maintaining inventory of both sizes of containers may exceed the savings associated with using a cheaper container for smaller orders.

8 0
3 years ago
What will it cost to tile a rectangular floor measuring 280 feet by 27 feet if the tile costs $11 per square foot. Round to the
lawyer [7]

Answer:

687

Step-by-step explanation:

First, we want to find the area of the rectangle.

The formula is length times width, so it is 27*280, which equals 7560. We divide this by 11 to get 687.27272727.....(repeating)

The answer is 687.

7 0
3 years ago
g Suppose that a die is rolled twice. What are the possible values that thefollowing random variables can take on:(a) the maximu
KengaRu [80]

Answer:

(a) A = {1, 2, 3, 4, 5, 6}

(b) B = {1, 2, 3, 4, 5, 6}

(c) C = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(d) D = {-5, -4, -3, -2, -1, -0, 1, 2, 3, 4, 5}

Step-by-step explanation:

Assume each roll can result in the numbers 1, 2, 3, 4, 5, or 6.

(a) If both rolls result in a 1, the maximum value is 1. If either roll results in a 6, the maximum value is 6; all integers between 1 and 6 are also possible. Therefore, the possible values are:

A = {1, 2, 3, 4, 5, 6}

(b) If either roll results in a 1, the minimum value is 1. If both rolls result in a 6, the minimum value is 6; all integers between 1 and 6 are also possible. Therefore, the possible values are:

B = {1, 2, 3, 4, 5, 6}

(c) If both rolls result in a 1, the sum is 2. If both rolls results in a 6, the sum is 12; all integers between 2 and 12 are also possible. Therefore, the possible values are:

C = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(d) If the first roll results in a 1 and the second results in a 6, the result is -5. On the other hand, if the first roll results in a 6 and the second results in a 1, the result is 5; all integers between -5 and 5 are also possible. Therefore, the possible values are:

D = {-5, -4, -3, -2, -1, -0, 1, 2, 3, 4, 5}

7 0
3 years ago
2x+y=5<br> -x+2y=4 <br><br> How do you solve this
d1i1m1o1n [39]
The answer to your problem is
x=5/2
y=5

x=-4
y=2
7 0
4 years ago
Mr Kobe has 30 students in his class ha has twice as many girls and boys what are the ratios to total students
Korvikt [17]

Answer:

Step-by-step explanation:

2:3 is the correct answer

7 0
3 years ago
Read 2 more answers
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