That would simply be
38.14 ÷ 4 = 9.535
thus he scored 9.535 on each event
Answer:
I think its a) I only
Step-by-step explanation:
b gives a random value that isn't relevant to the question. C is backwards because F would increase more than C.
We want to find

, for

.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)

.
The larger value is 9 x 10^9
The smaller value is 3 x 10^(-4)
Divide the larger over the smaller
Doing so will have you divide the coefficients 9 and 3 (numbers in front of the "times ten to the..." portions) to get 9/3 = 3.
Then you'll also subtract the exponents: 9 minus (-4) = 9 - (-4) = 9 + 4 = 13
In summary so far, we got a coefficient of 3 and an exponent of 13
So the final answer is 3 x 10^13 (assuming you want scientific notation)
If you want to convert to standard notation, instead of scientific notation, move the decimal point in 3.0 thirteen spots to the right to get
30,000,000,000,000
there are 13 zeros (four groups of 3 plus one just after the 3) in that value above. This is the number 30 trillion