Answer:
y=2/3x-5
Step-by-step explanation:
First, let's put this equation into slope-intercept form.
2x-3y=24
-3y=-2x+24
y=2/3x-8
For two lines to be parallel, they must have the same slope. Therefore our slope is 2/3.
Now, we must find b. To do that we can plug the y and the x in.
-7=2/3(-3)+b
-7=-2+b
-5=b
y=2/3x-5
Answer:
tan(x-y) = -16/63
Step-by-step explanation
Tan(x-y) if cscx=13/5 and coty=4/3
Given
coty = 4
1/tany = 4/3
Cross multiply
tan y = 3/4
Also since cscx = 13/5
1/sinx = 13/5
sinx = 5/13
Since sinx = opp/hyp
opp = 5
hyp = 13
Get the adjacent
hyp² = opp²+adj²
13² = 5²+adj²
adj² = 13² - 5²
adj² = 169 - 25
adj² = 144
adj = 12
cosx = adj/hyp
cosx = 12/13
tanx = sinx/cosx
tanx = (5/13)/(12/13)
tanx = 5/13 * 13/12
tan x = 5/12
tan(x-y) = tanx - tany/1+tanxtany
tan(x-y) = (5/12 - 3/4)/1+(5/12)(3/4)
tan(x-y) = (5-9/12)/1+5/16
tan(x-y) = -4/12/(21/16)
tan(x-y) = -1/3 * 16/21
tan(x-y) = -16/63
For problem 2, you are correct in stating that a curve forms. Specifically, if we were to trace along the outer edge of the shape, then we'd form a <u>parabola</u> that has been tilted 45 degrees compared to the more familiar form that students are taught (where the axis of symmetry is vertical).
For more information, search out "Tangent method for parabolas". As the name implies, the tangent method draws out the tangents of the parabola which helps form the parabola itself.
Everything else on your paper is correct. You have problem 1 correct, and the table is filled out perfectly. Nice work.
