Answer: 12
Step-by-step explanation:
I will assume those are coordinates.
The distance between 2 points is given by √ (x2 − x1)^2 + (y2 − y1)^2.
Replacing the values, we get √ (5 − 5)^2 + (6 − -6)^2 = √0+144 = 12
Volume of cone= 1/3 πr²*h
15²=10²+h²
h²=15²-10²=125
h=√125
Volume of cone= 1/3 *π*100*√125=π/3*(100*5√5)=500π√5/3
Volume of sphere=4/3*π*r³=4/3*π*1000=4000π/3
Volume of half sphere=(4000π/3)/2=2000π/3
All Volume=500π√5/3+2000π/3
If anyone has seen the answers to this question then I need please post it
Answer:
Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.
Step-by-step explanation:
Point A is (-4,6)
Point B is (-12,-12)
Point C is (6,-18)
Point D is (13,-1)
Given that the diagonals of a square are perpendicular to each other;
We know that the product of slopes of two perpendicular lines is -1.
So, slope(m) of AC × slope(m) of BD should be equal to -1.
Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4
Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44
The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056
Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.
V=lxwxh. 15x19x169= 48,165, which doesn't seem to be an answer
