Answer:
Q1
slope=0.16
intercept=30.2
Q2
78.2
Q3
36%
Step-by-step explanation:
Question 1
We are given that
xbar=280
sx=30
ybar=75
sy=8
r=0.6
The regression line can be written as
y=a+bx
a=intercept
b=slope
where
and
b=0.6*(8/30)
b=0.16
a=75-0.16*280
a=30.2
Thus,
slope=0.16
intercept=30.2
Question 2
The regression line in the given scenario
y=30.2+0.16x
Julie pre exam total before the exam was 300.
y=30.2+0.16*300
y=30.2+48=78.2
So, the predicted final exam score of Julie is 78.2.
Question 3
R² denotes the variation in dependent variable y explained by the linear relationship of x and y.
R²=0.6²=0.36
Thus, the proportion of the variation in final exam scores that is explained by the linear relationship between pre-exam scores and final exam scores is 36%.
Answer:
p(x) = (x - 5)(x + 5) + 20
Step-by-step explanation:
(x² - 5) ÷ (x - 5) ⇒ we put zero in place of x in the dividend
(x² + 0 - 5) ÷ (x - 5) = x + (5x - 5) ÷ (x - 5)
= (x + 5) + 20 ÷ (x - 5)
The quotient = (x + 5) ⇒ q(x)
The remainder = 20 ⇒ r(x)
The divisor = (x - 5) ⇒ d(x)
∴ p(x) = (x - 5)(x + 5) + 20
Answer:
its 28
Step-by-step explanation:
C is the longest side which is 35 ye and b is 21 yd. Then you would subtract 21^2 from 35^2 and you would get 784. Then find the square root of 784 and you would get 28 as the answer! Good luck and have a great day or night!
Answer:
Length AB = 1
Length CD = 3
Length EF = 2
Step-by-step explanation:
To get the length of each line segments we will use the formula for finding the distance between two points as shown:
D = √(x2-x1)²+(y2-y1)²
For line segment A = (3,5) and B = (3,6)
x1 = 3, y1 = 5, x2 = 3, y2 = 6
AB = √(3-3)²+(6-5)²
AB = √0+1²
AB = √1
AB = 1
For line segment C = (-2,-3) and D = (-2,-6)
CD =√(-2-(-2))²+(-6-(-3))²
CD = √0²+(-3)²
CD = √9
CD = 3
For line segment E = (-3,1) and F = (-3,-1)
EF = √(-3-(-3))²+(-1-1)²
EF = √0²+(-2)²
EF = √4
EF = 2
