Answer:
a is 622
Step-by-step explanation:
Answer:
The 95% confidence interval for mean compressive strength is:

Step-by-step explanation:
We have a sample of n=12 specimens, with sample mean=3259.9 and sample standard deviation = 35.57.
We know the population is normally distributed.
For a 95% confidence interval and df=n-1=11, the t-statistic is t=2.201.
Then, the CI can be expressed as:

Answer:
The answer is 9%
Step-by-step explanation:
18
200
x 100% = 9%
I turned 200 into 100% and if you divide 18 by 2 you can get 9
Hope this helped if you need more info let me know!!
5 2/3 + 2 1/5 = 118/15
= 7 13/15
Answer:
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Step-by-step explanation:
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