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3 years ago

3 1/2 pounds of honey ham for $10.25

Mathematics

1 answer:

Elodia [21]3 years ago

4 0

Answer:

2 2/3 pounds for $6.50 is the better deal

Step-by-step explanation:

10.25/3.5=2.93 a pound

6.50/2.66=2.44 a pound

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Use synthetic division to find (5x<br> + 31x + 32) = (x + 5).

LiRa [457]

We move all terms to the left:
+31x+32)-((+5)=0
So your answer is 0

5 0

3 years ago

Write the trigonometric expression <br> Cos (arcsin (u))<br> As an algebraic expression in u

makvit [3.9K]

When we use arcsine, we are finding the angle while giving the trigonometric ratio.

Arcsin(u) = theta can be rewritten as:

sin(theta) = u

Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.

We can use Pythagorean Theorem to find the adjacent (x value).

1^2 - u^2 = x^2

x = sqrt(1-u^2)

Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).

Cosine is adjacent over hypotenuse.

So our answer is sqrt(1-u^2)/1

Or just sqrt(1-u^2)

5 0

3 years ago

Use a calculator or a square root table to approximate to the nearest thousandth

Vadim26 [7]

Answer:

- 13.077

Step-by-step explanation:

Here we have to calculate the square root of a certain number using the help of the calculator or a square root table.

The given expression is $- \sqrt{ 171 }$ .

Now, using calculator $\sqrt{ 171 } = 13.076696$

Now, $- \sqrt{ 171 } = - 13.076696$

So, approximate value to the nearest thousandth is - 13.077 ( Answer )

4 0

3 years ago

Let f(x)=1/x and g(x)=x^2-2. What is (fog)(-3)?

Elenna [48]

Answer:

Its value is 1/7.

I hope this will help you.

3 0

3 years ago

The amount of time Ricardo spends brushing his teeth follows a Normal distribution with unknown mean and standard deviation. Ric

Papessa [141]

Let $X$ denote the number of minutes spent brushing his teeth, and let $\mu$ be the mean and $\sigma$ the standard deviation for this distribution.

$\mathbb P(X$

The z-score corresponding to this probability is approximately $z=-0.2533$ , which means

$\dfrac{1-\mu}\sigma=-0.2533\iff\mu-0.2533\sigma=1$

Next, (note the sign change)

$\mathbb P(X>2)=0.02\implies\mathbb P(X\le2)=\mathbb P\left(\dfrac{X-\mu}\sigma\le\dfrac{2-\mu}\sigma\right)=0.98$

The corresponding z-score is approximately $z=2.0538$ , so you have

$\dfrac{2-\mu}\sigma=2.0538\iff\mu+2.0538\sigma=2$

Solving the two equations for $\mu$ and $\sigma$ , you'll find that the mean is approximately $\mu=1.1098$ and the standard deviation is approximately $\sigma=0.4334$ .

7 0

3 years ago