At a track meet with 200 participants, 45 participate in jumping event, 1/3 of these jumpers are female, and 1/2 of the the tota
1 answer:
Answer:
The correct answer is 0.15.
Step-by-step explanation:
Total number of participants for the track meet = 200
Number of females among the participants = × 200 = 100
Number of persons participate in the jumping event = 45
Number of females among these jumper = × 45 = 15
Therefore the number of female jumpers are 15 out of the 100 female participants for the track meet.
Therefore the probability that a participant chosen at random is a jumper, given that the person is a female is = 0.15
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Answer:
Step-by-step explanation:
Birth Rate in 1994 = 14.6 births per thousand population.
Birth Rate in 2004 = 14.32 births per thousand population.
A linear equation is of the form: y=mx+c
Where:
- x=years after 1994
- y=the birth rate
- m=Yearly Birth Rate
First, we determine the birth rate per year
Therefore, a linear equation that relates y in terms of x is of the form:
When x=0, y=14.6
14.6=-0.028(0)+c
c=14.6
Therefore, the linear equation that relates y in terms of x is: