The triangle JOY is translated to another triangle which each points is moved to the right by 3 and moved downward by 2. So if a two segments is connected of two of each points, the result is that they have the same length and they are parallel to each other. So the answer is C.
Answer:
Angle of elevation: 68.2°, distance from Mr. clanton to the eagle: 32.3m.
Step-by-step explanation:
I can't draw the diagram , but will try to explain:
the diagram is a right angled triangle, with the opposite as the rig, the adjacent as the distance between mr. clinton and the base of the rig, and the hypotenuse as x.
∅ is the angle of elevation from clinton to the eagle.
Using SOH CAH TOA,
Tan∅ =30÷12
tan∅ =2.5.
∅ =tan^-1( tan raised to power -1 )
∅ =tan^-1(2.5)
∅ = 68.19859051≅68.2 to 3s.f.
To get the distance between mr. clinton and the eagle:
Using SOH CAH TOA;
Cos68.2 =12/x cross multiplying....
x*cos68.2 =12
∴ x = 12 ÷ cos 68.2
= 12 ÷ 0.3713678356
= 32.31297611≅32.3 to 3s.f.
Hope this helps.....
Tan(30°) = 17/x
x = 17/tan(30°) = 17√3
The hypotenuse of the smaller triangle is as you show, 34.
sin(45°) = 34/y
y = 34/sin(45°) = 34√2
x = 17√3
y = 34√2
Answer:
Step-by-step explanation:
1) angle GLH = angle JLI. This is so because they are vertically opposite angles.
angle JLI = 30 degrees. Therefore,
angle GLH = 30 degrees.
2) The sum of angles at a point is 360 degrees. It means that
Angle HLI + angle JLI + angle KLJ + angle GLK + angle HLG. Therefore,
Angle HLI + 30 + 60 + 90 + 30 = 360
Angle HLI + 210 = 360
Angle HLI = 360 - 210 = 150 degrees
3) angle ILK = 60 + 30 = 90 degrees