Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer:
1571 in
Step-by-step explanation:
Given data
Diamter= 25 in
radius= 25/2= 12.5in
Circumference= 2πr
substitute
C=2*3.142*12.5
C=78.55in
In 1 revolution the bike will travel 78.55in
in 20 revolutions the bike will travel
=78.55*20
=1571 in
Answer:
120 ft³
Step-by-step explanation:
volume= 
(l×w×h)
= (9×4×5)
= 120 ft³
The first one, the fourth one, and the middle one
