Question

Two equations are shown: Equation 1: 3 4 (x−12)=12 Equation 2: 3 4 y−12=12 Solve each equation. Then, enter a number in each box to make this statement true. The value of x is:
The value of y is:

Answer 1

Answer:

The value of x is 28.

The value of y is 32.

Step-by-step explanation:

Given : Equation 1 - $\frac{3}{4}(x-12)=12$

Equation 2 - $\frac{3}{4}y-12=12$

To find : Solve each equation ?

Solution :

Equation 1 - $\frac{3}{4}(x-12)=12$

Apply distributive property, $a(b-c)=ab-ac$

$\frac{3}{4}x-\frac{3}{4}\times 12=12$

$\frac{3}{4}x-3\times 3=12$

$\frac{3}{4}x-9=12$

$\frac{3}{4}x=12+9$

$\frac{3}{4}x=21$

$x=\frac{21\times 4}{3}$

$x=28$

Equation 2 - $\frac{3}{4}y-12=12$

Add 12 both side,

$\frac{3}{4}y-12+12=12+12$

$\frac{3}{4}y=24$

$y=\frac{24\times 4}{3}$

$y=32$

The value of x is 28.

The value of y is 32.

Answer 2

Answer:

The value of X =  24

The value of y = 24

Step-by-step explanation:

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