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1 year ago

This number has a 0 in the ones

1 answer:

8 0

Based on the numbers that the decimal contains, and the positioning of the numbers, the number can be found to be 0.54123.

<h3>What number is it?</h3>

The 0 is in the tens place which means that it is the only number to the left of the decimal point.

The fifth digit to the right of the decimal sign is smaller than the first which means that it cannot be 5.

The number in the thousandth(3rd place) is the smallest number which makes it 1.

The number in the ten thousandths(4th) place is half the value of the number in the hundredths place(2nd) which means that the hundredths number can only be 4 and the ten thousandth number is 2.

The decimal is therefore:
= 0.54123

Find out more on solving for numbers at brainly.com/question/19389558.

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I have no idea. Please I need just answers. Thank you.

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Answer:

Step-by-step explanation:

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3 years ago

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Answer:

Simplify the expression.

Exact Form:

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Decimal Form:

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Add-on:

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3 years ago

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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

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Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

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So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

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Step-by-step explanation:

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