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Cloud [144]
4 years ago
7

Girls backyard is in the shape of a rectangle that has a length of 19.5 ft it cost 945 to fence in the yard if the cost is $15 p

er foot what is the width of Carol backyard
Mathematics
1 answer:
alisha [4.7K]4 years ago
8 0
You need to know the formula for the perimeter of a rectangle. We won't use it right away, but it is pertinent information.P = 2 ( l + w )Now, we know that the fencing costs $15.00 per foot, and that the length is 19.50 feet. We first need to find the price of one "length" side of the fence. To do this, multiply 19.50 by 15.0019.50 x 15.00 = 292.5Next, we look at the perimeter equation to see what we can plug in where.P = 2 ( l + w )We can put in the total price of the fencing for the yard as P, and the amount of one length side of the fence as l.945.00 = 2 ( 292.5 + w )And now, we simply solve for w.945.00 ÷ 2 = ( 2 ( 292.5 + w ) ) ÷ 2472.5 = 292.5 + w472.5 - 292.5 = 292.5 + w - 292.5w = 180It costs $180 for one "width" side of the fence. To find out how many feet that is, we do the opposite of what we did with the length. Instead of multiplying by $15.00, we divide by $15.00$180.00 ÷ $15.00 = 12The width of Claire's backyard is 12 feet

HOPE THIS HELPS :)
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Answer:

x= 1

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Step-by-step explanation:

8x + 9y = -28

-4x = y

8x + 9(-4x) = -28

8x - 36x = -28

-28x = - 28

x = 1

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Answer:

The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let C = (h,k) the coordinates of the center of the circle, which must be transformed into C'=(h', k') by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

(x-h)^{2}+(y-k)^{2} = r^{2}

Where r is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

C''(x,y) = C(x, y) + U(x,y) (Eq. 1)

Where U(x,y) is the translation vector, dimensionless.

If we know that C(x, y) = (h,k) and U(x,y) = (4, 0), then:

C''(x,y) = (h,k)+(4,0)

C''(x,y) =(h+4,k)

2) <em>Reflection over the x-axis</em>:

C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)] (Eq. 2)

Where O(x,y) is the reflection point, dimensionless.

If we know that O(x,y) = (h+4,0) and C''(x,y) =(h+4,k), the new point is:

C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]

C'(x,y) = (h+4, 0)-(0,k)

C'(x,y) = (h+4, -k)

And thus, h' = h+4 and k' = -k. The statement is now presented as:

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I hope this helps!

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Answer:

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75 - 3.5x - 4x = 4x + 6

Step 2: Solve for <em>x</em>

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Step 3: Check

<em>Plug in x to verify it's a solution.</em>

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