3 years ago

What is the circumference of the the navy pier ferris wheel

Mathematics

1 answer:

Arisa [49]3 years ago

6 0

Do you have a graph on that

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What is the discriminant of the equation -4.9t^2+6.1t-0.8=0

vlabodo [156]

$\sqrt{6.1^2-4*-4.9*-0.8}$ ≈ 4.64

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3 years ago

WRITE AN EQUATION FOR EACH OF THESE AND SOLVE IT TO FIND THE VALUE OF THE UNKNOWN NUMBER:

castortr0y [4]

a) a *5+5= 20

5a + 5 = 20

5a = 20 - 5

5a = 15

a = 15/5

a = 3

b) b/5 - 5 = 4

b/5 = 4 + 5

b/5 = 9

b =9*5

b = 45

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2 years ago

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What is the slope and y intercept?

natka813 [3]

The y intercept is -2.

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2 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

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2 years ago

How do i make 5x+2y=4 into the form of y=mx+b

malfutka [58]

First you minus 2y on both sides and you get: 5x=-2y+4. Then you minus 4 on both sides to get 5x-4=-2y which in turn is y (-2y) = mx (5x) + b (-4) : -2y=5x-4

6 0

3 years ago