<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
Answer:
right
Step-by-step explanation:
69 + 21 is equal to 90 and all three angle of a triangle will be 180 so the last angle would be 90. And a right triangle will have an angle = to 90
Answer:
At the moment it is thrown, the height of the ball is 12 meters
Step-by-step explanation:
If the function 
models the height of the ball x seconds after it is thrown, then by this same function we can know the initial height of the ball at the initial moment.
If we represent the initial time instant as x = 0, then by doing h (0) we will get the initial height, just when the ball is thrown.
h (0) = 12 meters.
At the moment it is thrown, the height of the ball is 12 meters
