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Karo-lina-s [1.5K]
3 years ago
10

PLEASE HELP WITH THIS QUESTION

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0

I think the correct answer is c

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The problem is 
Sophie [7]
average=\frac{sum\ of\ attendance}{amount\ of\ shows}\\\\
average=3000\\\\
3000=\frac{2580+2920+third\ show}{3}\ \ \ |*3\\
9000=2580+2920+third\ show\\
9000=5500+third\ show\ \ \ |Subtract\ 5500\\
3500=third\ show\\\\
\textbf{3500\ people\ must\ attend\ the\ third\ show.}
7 0
3 years ago
At a hospital, 56 percent of the babies born are boys. Of the baby girls born, 12 percent are premature. What is the probability
Mrac [35]

Answer:

Answer: First Option (5%)

Step-by-step explanation:

5 0
3 years ago
In the coordinate plane, you are given JKL with J(2, 3), K(10,4), and L(6, 10). Using the distance formula, classify JKL
Marrrta [24]

Answer:

Perimeter of JKL = 22.55 unit (Approx.)

Step-by-step explanation:

Given:

Coordinate of J = (2,3)

Coordinate of K = (10,4)

Coordinate of L = (6,10)

Find:

Perimeter of JKL

Computation:

Distance = √(x1 - x2)² + (y1 - y2)²

Distance between JK = √(2 - 10)² + (3 - 4)²

Distance between JK = √64 + 1

Distance between JK = √65

Distance between JK = 8.06 unit

Distance between KL = √(10 - 6)² + (4 - 10)²

Distance between KL = √16 + 36

Distance between KL = √52

Distance between KL = 7.21 unit

Distance between LJ = √(6 - 2)² + (10 - 3)²

Distance between LJ = √4 + 49

Distance between LJ = √53

Distance between LJ = 7.28 unit

Perimeter of JKL = Distance between JK + Distance between KL + Distance between LJ

Perimeter of JKL = 8.06 + 7.21 + 7.28

Perimeter of JKL = 22.55 unit (Approx.)

4 0
2 years ago
Given the following equation answer each question below.
Ahat [919]

Answer:

f(x)=

Step-by-step explanation:

7 0
2 years ago
What is the measure for the following ∠?<br> m∠EOD<br><br> 20<br> 120<br> 140
Eddi Din [679]

Answer:

Part 1) m∠EOD=20°

Part 2) m∠AOD=80°

Step-by-step explanation:

Part 1) Find the measure of angle EOD

we know that  °

m∠EOD=m∠EOX-m∠DOX

we have

Observing the figure

m∠EOX=140°

m∠DOX=120°

substitute

m∠EOD=140°-120°=20°

Part 2) Find the measure of angle AOD

we know that  °

m∠AOD=m∠DOX-m∠AOX

we have

Observing the figure

m∠AOX=40°

m∠DOX=120°

substitute

m∠AOD=120°-40°=80°

8 0
3 years ago
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