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Elina [12.6K]
3 years ago
10

Which is true of a substance with a lot of mass:

Chemistry
2 answers:
weeeeeb [17]3 years ago
6 0

Answer:

i has a large density

Explanation:

i looked it up

pochemuha3 years ago
4 0
B has a large density
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Do you think one mole of the different substances has the same amount?​
vagabundo [1.1K]

It's because of Avagadro's number.

  • It is known as Avagadro's constant too.
  • It states that at constant temperature one mole of any substance contain same number of atoms i.e n no of atoms

where

\\ \sf\longmapsto n=6.022\times 10^{23}

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2 years ago
Use your periodic table and calculator as needed for the following question.
sveticcg [70]
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7 0
4 years ago
What is the name of this molecule?
Sunny_sXe [5.5K]

Answer:

D. cis-2-pentene (looks like a frying pan)

Explanation:

pentane looks lihe the letter M

2-methylpentane looks like YV

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8 0
3 years ago
The half life for the first order conversion of A to B is 56.6 hours. How long does it take for the concentration of A to decrea
sveta [45]

Answer:

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

Explanation:

A → B

Initial concentration of the reactant = x

Final concentration of reactant = 10% of x = 0.1 x

Time taken by the sample, t = ?

Formula used :

A=A_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

A_o = initial concentration of reactant

A = concentration of reactant left after the time, (t)

t_{\frac{1}{2}} = half life of the first order conversion  = 56.6 hour

\lambda = rate constant

A=A_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

0.1x=x\times e^{-(\frac{0.693}{56.6 hour})\times t}

t = 188.06 hour

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

4 0
3 years ago
What is the percent by mass of oxygen in carbon dioxide
san4es73 [151]
C = 12
O2 = 16*2= 32
CO2 = (12)+(16*2) = 44

32/44*100 = 72.73%
6 0
3 years ago
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