What mass is 8.9 moles of Ca?<br> 0.22<br> mole(s)<br> 8.9 moles of Ca x<br> grams<br> 8.9<br> grams

Melissa and ashley play tennis every afternoon. Twenty minutes into the game they both start to breath heavy, sweat, and feel th

marysya [2.9K]

Answer:

B. Respiratory and Circulatory

I'm pretty sure

Explanation:

6 0

2 years ago

For the chemical equation SO 2 ( g ) + NO 2 ( g ) − ⇀ ↽ − SO 3 ( g ) + NO ( g ) the equilibrium constant at a certain temperatur

MakcuM [25]

Answer:

Moles of NO₂ = 0.158

Explanation:

SO 2 ( g ) + NO 2 ( g ) ⇄ SO 3 ( g ) + NO ( g )

According to the law of mass equation

$K_{c}$ = $\frac{[SO_{3} ][NO]}{[SO_{2}][NO_{2} ]}$

⇒ 3.10 = $\frac{(1.00)(1.00)}{(2.30) [NO_{2} ]}$ At equilibrium [SO₃] = [NO]

⇒ [NO₂] = $\frac{1}{6.3}$

⇒ [NO₂] = 0.158

So. number of moles of NO₂ at equilibrium added = 0.158

8 0

3 years ago

A gas with a volume of 4.0 liters at a pressure of 205 kilopascals is allowed to expand to a volume of 12.0 liters. What will th

Ksenya-84 [330]

Boyle's law p1V1=p2V2

p2=(p1V1)/V2

p2=(205*10^3 Pa * 4*10^-3 m^3 ) / (12*10^-3 m^3)

p2= 68333 Pa

8 0

3 years ago

Complete the chemical change. _______ + e - → Cl-

Sedaia [141]

You are left with a chloride ion, so you started off with a chlorine atom.
Cl + e- → Cl-

3 0

3 years ago

Read 2 more answers

Which formula is an empirical formula?

poizon [28]

<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. $NH_{3}$

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

$MolecularFormula=n(EmpiricalFormula)$

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. $N_{2}O_{4}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$N_{2}O_{4}=2(NO_{2})$

B. $NH_{3}$

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. $C_{3}H_{6}$