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skad [1K]
3 years ago
13

Find each absolute value. |6-3|

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0
When you take the absolute value of this equation, the answer should actually be 3.

You should solve the what’s inside first. If the answer is negative, then the absolute value will make it positive.

For example

|1-5|=|-4|=4
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Which change will quadruple the lateral surface area of a cone?
vlada-n [284]
Don't know try something else it will probably help
6 0
3 years ago
Read 2 more answers
When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
Find The surface area of a cone with a radius of 7 and slant hight of 9
liubo4ka [24]

Answer:14

Step-by-step explanation:

4 0
3 years ago
Question in pic! help asap!! will give brainliest!!
Ne4ueva [31]
11,340 I believe. 5% of 8400 is 420. 420*7=2940 2940+8400=11340
7 0
3 years ago
Given the function f(x) = 6x^2 −13, what is f(-3)?
Naya [18.7K]
<h3>Answer: 41</h3>

Work Shown:

f(x) = 6x^2 - 13

f(x) = 6(x)^2 - 13

f(-3) = 6(-3)^2 - 13 ... replace every x with -3; use PEMDAS to simplify

f(-3) = 6(9) - 13

f(-3) = 54 - 13

f(-3) = 41

7 0
3 years ago
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