For the mode to be 6, there has to be at least two 6s.
For the median to be 6, with two 6s, there must be at least one number above 6.
For the mean to be 6, the sum is 30, so the three remaining numbers must total 18.
9 is the answer negatives cancel out creating positve
We can't eliminate as is so we have to change something up there in the equations to get either the x values the same number but opposite signs, or the y values the same number but opposite signs. I chose to change the y values to the same number but different signs. In the first equation y is -3y and in the second one, y is -8y. The LCM of both of those numbers is 24, so we will multiply the first equation by an 8 (8*3=24) and the second equation by 3 (3*8=24) but since they are both negative right now, one of those multiplications has to involve a negative because - * - = +. Set it up like this:
8(-10x - 3y = -18)
-3(-7x - 8y = 11)
Multiply both of those all the way through to get new equations:
-80x - 24y = -144
21x +24y = -33
Now the y's cancel each other out leaving only the x's:
-59x = -177 and x = 3. Now plug that 3 into either one of the original equations to find the y value. Either equation will work; you'll get the same answer using either one. Promise. -7(3) - 8y = 11 gives a y value of -4. so your solution is (3, -4) or B above.
Answer:
The correct answer is (5 - 7)^2
Step-by-step explanation:
To find this, start with the outermost equation g(x).
g(x) = x^2
Now put the next equation (h(x)) in for x in this equation.
(G ▪ H)(x) = (x - 7)^2
Now, put the number in for x in the equation given.
(G ▪ H)(x) = (5 - 7)^2
