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allsm [11]
3 years ago
9

Which of the following ordered pairs is not a solution of the system of inequalities? y > x2 – 4x – 5 y < –x2 – 5x + 6 Que

stion 62 options: A) (1, 7) B) (1, –7) C) (1, –5) D) (–1, 6)
Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

a) (x, y) = (1, 7)

Step-by-step explanation:

Let be the following system of inequalties:

y > x^{2}-4\cdot x -5

y < -x^{2}-5\cdot x +6

We can find the right option by evaluating each option in the system of inequalities:

a) (x, y) = (1, 7)

7 > 1^{2}-4\cdot (1) -5

7 < -1^{2}-5\cdot (1) +6

Then,

7>-8 (TRUE)

7 (FALSE)

(1, 7) is not a solution of the system of inequalities.

b) (x, y) = (1, -7)

-7 > 1^{2}-4\cdot (1) -5

-7 < -1^{2}-5\cdot (1) +6

Then,

-7 > - 8 (TRUE)

-7< 0 (TRUE)

(1, -7) is a solution of the system of inequalities.

c) (x, y) = (1, -5)

-5 > 1^{2}-4\cdot (1) -5

-5 < -1^{2}-5\cdot (1) +6

Then,

-5 > - 8 (TRUE)

-5< 0 (TRUE)

(1, -5) is a solution of the system of inequalities.

d) (x, y) = (-1, 6)

6 > (-1)^{2}-4\cdot (-1) -5

6

Then,

6>0 (TRUE)

6 < 12 (TRUE)

(-1, 6) is a solution of the system of inequalties.

Therefore, we conclude that correct answer is A.

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