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atroni [7]
3 years ago
15

Jean and Clint stack boxes at a warehouse. Jean stacks 50 boxes per hour. Clint stacks 60 boxes per hour. Which of the following

expressions represent the total number of boxes that both jean and clint stack in h hours, where h is any number of hours?
Mathematics
1 answer:
Valentin [98]3 years ago
5 0
Represent the total number of boxes that both jean and clint stack in h hours,

total number of boxes=(50xh)+(60xh)
you want the total number of boxes for both of them together. so the amount they can stack times h or the hours. so if h=5 you would do 50x5 plus+ 60x5 which would give you 250 and 300. add the two you get 550 boxes for 5 hours total.
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PLEASE HELP ASAP WILL MEDAL BRAINLIEST
Naddik [55]
Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A 

A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11

B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29


Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18

5 0
3 years ago
Is 6-6 and 1-6 equal
uranmaximum [27]

Answer:

no

Step-by-step explanation:

6-6=0

1-6=-5

7 0
3 years ago
A boy is Y years old. His father is twice as old as he is. The sum of their ages is 63. How old is the boy?
Arturiano [62]
Hi!
Divide 63 by 3. You will get 21. That is the boys age. His father’s age is 42. When combined their age is 63.
3 0
2 years ago
Read 2 more answers
A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert
andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of ​​the circular sector using the following equation.(c in the second attached image)

A=\frac{R^2}{2} (\alpha -sin\alpha )

\alpha =2arccos(\frac{d}{R})

3. observing the attached images we replace the values ​​in the equations and find the area of ​​the circular sector, remember that you must transform the angle to radians

\alpha =2arccos(\frac{5}{7})=88.83

A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2

4.we calculate the area of ​​the total circle (At), then subtract the area of ​​the circular sector (Ac) to find the area occupied by water (Aw)

At=\frac{\pi }{4} (14ft)^2=153.93ft^2

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of ​​the water over the total area of ​​the tank

\frac{116.36}{153.93} *100=75.6

percentage of the total capacity is 75.6%

3 0
3 years ago
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
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