Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A
A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11
B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29
Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18
Answer:
no
Step-by-step explanation:
6-6=0
1-6=-5
Hi!
Divide 63 by 3. You will get 21. That is the boys age. His father’s age is 42. When combined their age is 63.
Answer:
percentage of the total capacity is 75.6%
Step-by-step explanation:
Hello! To solve this problem we follow the following steps
1. draw the complete scheme of the problem (see attached image)
2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)


3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians


4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

Aw=At-Ac=153.93-37.57=116.36ft^2
5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

percentage of the total capacity is 75.6%
Answer:
The required polynomial is
.
Step-by-step explanation:
If a polynomial has degree n and
are zeroes of the polynomial, then the polynomial is defined as

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.
According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.
Since 3-3i is zero, therefore 3+3i is also a zero.
Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is


![[a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5Ba%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)

![[i^2=-1]](https://tex.z-dn.net/?f=%5Bi%5E2%3D-1%5D)


Therefore the required polynomial is
.