A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
What do you mean about that?
Answer:
B. 85
Step-by-step explanation:
I haven't taken Geometry in 2 years So I don't remember how to explain it.
Answer:
Step-by-step explanation:
SIMPLE 30 X 30
Answer:
p=(0,2) q=(0.5,0)
Step-by-step explanation:
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PLS MARK BRAINLIEST
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