<span>Error bars within treatments illustrate confidence intervals, standard errors, standard deviations or other quantities. However, different types of error bars exist, so figure legends must be sure to distinguish which error bar is being represented. </span>
Answer:
Homologous pairs of cells are present in meiosis I and separate into chromosomes before meiosis II. In meiosis II, these chromosomes are further separated into sister chromatids. Meiosis I includes crossing over or recombination of genetic material between chromosome pairs, while meiosis II does not.
Explanation:
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Answer:
a. purple allele (C) = 0.609, pink allele (c) = 0.391
b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476
Explanation:
Given -
Purple flowers - 847
Pink flowers - 153
The frequency of recessive genotype i.e
Frequency of recessive allele i.e q is equal to
As per hardy Weinberg's first equilibrium equation -
Frequency of purple homozygous species
Number of purple homozygous species 
Number of pink homozygous species 
Heterozygous species is equal to
Answer:
The Lineweaver- Burk plot is representation of Lineweaver-Burk equation of enzyme kinetics in graphical plot that is presented by the Hans Lineweaver and Dean Burk.
In the presence of a non competitive inhibitor shows higher y-intercept than a control in absence of any inhibitor whereas the x intercept is the same as the control that suggests or tells that maximum enzyme activity of the reaction is decreased, Higher Y intercept than controls means that it is same as 1/Vmax. The X intercept indicates that there is no effect on Km of the enzyme reaction.
