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ivanzaharov [21]
3 years ago
8

Create a method called nicknames that passes an array as a parameter. Inside the method initialize it to hold 5 names of your ch

oice. Use the for each enhanced loop to print the elements of the array.
Computers and Technology
1 answer:
Gre4nikov [31]3 years ago
6 0
<h2>Answer:</h2>

    //======METHOD DECLARATION=========//          

    //method name: nicknames                                          

    //method return type: void                                            

    //method parameter: an array reference                    

    public static void nicknames(String [] names){      

       //initialize the array with 5 random names              

       names = new String[] {"John", "Doe", "Brian", "Loveth", "Chris"};

       //using an enhanced for loop, print out the elements in the array

       for(String n: names){

           System.out.print(n + " ");

       }

       

    }

<h2>Explanation:</h2>

The program is written in Java. It contains comments explaining important parts of the code. Kindly go through these comments.

A few things to note.

i. Since the method does not return any value, its return type is <em>void</em>

ii. The method is made public so that it can be accessible anywhere in and out of the class the uses it.

iii. The method is made static since it will most probably be called in the static main method (at least for testing in this case)

iv. The method receives an array of type <em>String </em>as parameter since the names to be stored are of type <em>String</em>.

v. The format of initializing an array manually should follow as shown on line 7. The <em>new</em> keyword followed by the array type (String), followed by the square brackets ([]) are all important.

vi. An enhanced for loop (lines 9 - 11) is a shorthand way of writing a for loop. The format is as follows;

=> The keyword <em>for</em>

=> followed by an opening parenthesis

=> followed by the type of each of the elements in the array. Type String in this case.

=> followed by a variable name. This holds an element per cycle of the loop.

=> followed by a column

=> followed by the array

=> followed by the closing parenthesis.

=> followed by a pair of curly parentheses serving as a block containing the  code to be executed in every cycle of the loop. In this case, the array elements, each held in turn by variable n, will be printed followed by a space.

A complete code and sample output for testing purposes are shown as follows:

==================================================

public class Tester{

    //The main method

    public static void main(String []args){

       

       String [] names = new String[5];

       nicknames(names);

    }

   

  //The nicknames method

    public static void nicknames(String [] names){

       names = new String[] {"John", "Doe", "Brian", "Loveth", "Chris"};

       for(String n: names){

           System.out.print(n + " ");

       }

       

    }

}

==================================================

<h2>Output:</h2>

John Doe Brian Loveth Chris

<em>NB: To run this program, copy the complete code, paste in an IDE or editor and save as Tester.java</em>

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Answer:

Explanation:

#include <iostream>

using namespace std;

int costdays(int);

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int main()

{

   int dd,hh,mm,tmph,tmpd,tmpm=0;

   int pcost,mcost=0;

   cout<<"Enter Parking time" << endl;

   cout<<"Hours: ";

   cin>>hh;

   cout<<"Minutes: ";

   cin>>mm;

   

   if (mm>60)

   {

       tmph=mm/60;

       hh+=tmph;

       mm-=(tmph*60);

   }

   if (hh>24)

   {

       tmpd=hh/24;

       dd+=tmpd;

       hh-=(tmpd*24);

   }

   if ((hh>4)&&(mm>0))

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       pcost+=costdays(1);

   }

   else

   {

       mcost=costhrs(hh,mm);

   }

   cout<<"Total time: ";

   if (dd>0)

   {

       cout<<dd<<"days ";

       pcost+=costdays(dd);

   }

   pcost+=mcost;

   cout<<hh<<"h "<<mm<<"mins"<<endl;

   cout<<"Total Cost :"<<pcost<<"Won";

   return 0;

}

int costdays(int dd)

{

   return(dd*25000);

}

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{

   int tmpm, tmp=0;

   tmp=(hh*6)*1000;

   tmp+=(mm/10)*1000;

   tmpm=mm-((mm/10)*10);

   if (tmpm>0)

   {

       tmp+=1000;

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3 years ago
What are the two categories of problems that we can simply convert<br> to parallel code?
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Percentage and decimals
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3 years ago
I Previous
Tcecarenko [31]

Answer:

D. Change the def to def area (width, height = 12)

Explanation:

Required

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To do this, we simply update the def function to:

def area (width, height = 12)

So:

In boxlarea = area (5,2), the area will be calculated as:

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5 0
2 years ago
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre
Fudgin [204]

Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

  // declaration of integer variables

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   // initialization of integer variables

   k=1, n=4, total=0;

//  loop executed till value of k becomes equal to value of n

   while( k <= n ){

       // cube of every integer is added to the variable total

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k = k + 1 ;

   }  

   return 0;

}  

Explanation:

The program begins with the declaration of integer variables.  

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

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First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

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After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

   }

When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.

When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

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damaskus [11]

Answer:

I belive the answer is E

Explanation:

8 0
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