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kipiarov [429]
3 years ago
7

The distance from your house to the ice cream shop is 12 miles. Your best friends house is on the segment between your house and

the ice cream shop, and his house is 3 miles from the ice cream shop. How many miles is your house from your best friends house?

Mathematics
1 answer:
AfilCa [17]3 years ago
4 0
See attachment

distance from ice cream to your house=distance from ice cream to friend+distance from friend to your house

distance from ice cream to your house=12
distance from ice cream to friend=?
distance from friend to your house=3

12=?+3
minus 3 both sides
12-3=?+3-3
9=?+0
9=?

answer is 9 miles

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<em>7 grams of sugar</em>

<h2>Explanation:</h2>

________________________________________

I'll assume your answer is as follows:

<em>A bowl of cereal had 3 3/6 grams of sugar in it. If Victor ate 2 bowl a week, how many grams of sugar would he have eaten?</em>

________________________________________

If so, then we know that:

  • A bowl of cereal had 3 3/6 grams of sugar in it.
  • Victor ate 2 bowl a week

In other words, the total of sugar he ate can be calculated as:

3\frac{3}{6}\times2 \\ \\ Converting \ mixed \ fraction \ into \ improper \ fraction: \\ \\ =(3+\frac{3}{6})\times2 \\ \\ =(\frac{3(6)+3}{6})\times 2 \\ \\ =(\frac{21}{6})\times 2 \\ \\ =(\frac{7}{2})\times 2 \\ \\ =7

So <em>he'd have eaten 7 grams of sugar</em>

<h2>Learn more:</h2>

Mixed numbers: brainly.com/question/383603

#LearnWithBrainly

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Cole bought 7 bricks. All together, the bricks weighed 95.26 pounds. To the nearest thousandth of a pound, how much did each bri
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How to find the derivative of cos^2x? i seem to be confused.
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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2927231

————————

You can actually use either the product rule or the chain rule for this one. Observe:

•  Method I:

y = cos² x

y = cos x · cos x


Differentiate it by applying the product rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x\cdot cos\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x)\cdot cos\,x+cos\,x\cdot \dfrac{d}{dx}(cos\,x)}


The derivative of  cos x  is  – sin x. So you have

\mathsf{\dfrac{dy}{dx}=(-sin\,x)\cdot cos\,x+cos\,x\cdot (-sin\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=-sin\,x\cdot cos\,x-cos\,x\cdot sin\,x}


\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark

—————

•  Method II:

You can also treat  y  as a composite function:

\left\{\!&#10;\begin{array}{l}&#10;\mathsf{y=u^2}\\\\&#10;\mathsf{u=cos\,x}&#10;\end{array}&#10;\right.


and then, differentiate  y  by applying the chain rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot \dfrac{du}{dx}}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=\dfrac{d}{du}(u^2)\cdot \dfrac{d}{dx}(cos\,x)}


For that first derivative with respect to  u, just use the power rule, then you have

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and then you get the same answer:

\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>derivative chain rule product rule composite function trigonometric trig squared cosine cos differential integral calculus</em>

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