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lina2011 [118]
4 years ago
13

#12 only please I need to turn this in tommorow help

Mathematics
2 answers:
alexandr1967 [171]4 years ago
7 0

Answer:

B hope it helps!

nordsb [41]4 years ago
6 0

Answer:

28/100 would be the answer.

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Lincoln invested $49,000 in an account paying an interest rate of 6\tfrac{1}{8}6
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Using compound interest and continuous compounding, it is found that Lincoln would have $15,856 more in his account than Eli.

<h3>What is compound interest?</h3>

The amount of money earned, in compound interest, after t years, is given by:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

In which:

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal value).
  • n is the number of times that interest is compounded per year.

Hence, for Lincoln, we have that the parameters are as follows:

P = 49000, r = 0.06125, n = 365, t = 20.

Hence the amount will be of:

A_L(t) = P\left(1 + \frac{r}{n}\right)^{nt}

A_L(20) = 49000\left(1 + \frac{0.06125}{365}\right)^{365 \times 20}

A_L(20) = 166787

<h3>What is continuous compounding?</h3>

The amount is given by:

A(t) = Pe^{rt}

For Eli, we have that r = 0.05625, hence the amount will be given by:

A(t) = Pe^{rt}

A_E(20) = 49000e^{0.05625 \times 20} = 150931

<h3>What is the difference?</h3>

It is given by:

D = A_L(20) - A_E(20) = 166787 - 150931 = 15856

Lincoln would have $15,856 more in his account than Eli.

More can be learned about compound interest at brainly.com/question/25781328

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