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Anika [276]
3 years ago
14

Can anyone help me on this please?

Mathematics
1 answer:
romanna [79]3 years ago
3 0

Answer:

x = 6

y = 12

z = 12√2

Step-by-step explanation:

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In a bag of candy, Marsha found that there were 7 red, 8 blue, 5 yellow, and 9 greens pieces of candy. Marsha put all of the pie
son4ous [18]

Answer:

Step-by-step explanation:

1) find the total candies

7 + 8 + 5 + 9 = 29

2) a probability can be expressed with a fraction whose denominator is the total candies, while the numerator represents the candies that we want to find

- red = 7/29

- blue = 8/29

- yellow = 5/29

- green = 9/29

3) compound probability

(red + blue)/29 = 15/29

(yellow + green)/29 = 14/29

(blue + yellow + green)/29 = 22/29

7 0
3 years ago
I need help asap :):):)
KiRa [710]

Answer:

24 ÷ 4

Step-by-step explanation:

Putting something into fourths is putting into 4 parts. If you divide 24 by 4 you get 6. 6 equals 1/4 of 24. To check your work add 6 together 4 times.

7 0
3 years ago
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Consider the given function and the given interval. f\(x\) = 2 sin\(x\) - sin\(2 x\) text(, ) [0 text(, ) pi] (a) Find the avera
Finger [1]

a. The average value of f on the given interval is

\displaystyle f_{\rm ave}=\frac1{\pi-0}\int_0^\pi(2\sin x-\sin2x)\,\mathrm dx=\boxed{\frac4\pi}

b. Solve for c:

\dfrac4\pi=2\sin c-\sin2c\implies\boxed{c\approx1.238\text{ or }c\approx2.808}

4 0
3 years ago
Donna has a $300 loan through the bank she is charged a simple rate The total interest she paid on the loan was $63 As a percent
Black_prince [1.1K]

Answer:

21%

Step-by-step explanation:

($63*100%) / $300 = 21%

3 0
2 years ago
The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?
AleksAgata [21]

Answer:

\large \boxed{2}

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}

Check:

\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}

It checks.

7 0
3 years ago
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