Given :
A sailor is 30 m above the water in the crow's nest on a sailboat.
The sailor encounters an orca surface at an angle of depression of 15 degrees.
The crows nest is 20 m horizontally from the bow (front) of the boat.
To Find :
How far in front of the boat is the orca.
Solution :
Let, distance of boat front from the crow's nest is x.
So,

Hence, this is the required solution.
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
Answer:
(x+6)(y+3)
Step-by-step explanation:
- xy + 3x + 6y + 18
- x(y + 3) + 6(y+3)
- <u>(</u><u>x</u><u>+</u><u>6</u><u>)</u><u>(</u><u>y</u><u>+</u><u>3</u><u>)</u>
Answer:
0.318
Step-by-step explanation:
The answer to number 2 is g.15