Can someone, anyone, help me?

The ratio using a colon is

anyanavicka [17]

a ratio?

What numbers a provided

7 0

3 years ago

You work in billing Insuranse 83% deductible what will you multiply by to see what the patient paid

maks197457 [2]

Answer:

0.17

Step-by-step explanation:

The billing department of Insurance is my workplace.

It is said that 83% of the bill amount is deductible from it.

If the amount is P and 83% is deductible from it then the amount becomes $P - P \times \frac{83}{100}$

= $P[1-0.83]$

= 0.17P

Therefore, we have to multiply 0.17 with the amount to see what the patient paid. (Answer)

6 0

3 years ago

Trials in an experiment with a polygraph include 98 results that include 23 cases of wrong results and 75 cases of correct resul

Evgen [1.6K]

Answer:

$z=\frac{0.765 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-0.866$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of correct cases is not significantly lower than 0.8 or 80%

Step-by-step explanation:

Data given and notation

n=98 represent the random sample taken

X=75 represent the number of correct cases

$\hat p=\frac{75}{98}=0.765$ estimated proportion of correct cases

$p_o=0.8$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.8 or not.:

Null hypothesis: $p \geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.765 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-0.866$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of correct cases is not significantly lower than 0.8 or 80%

4 0

4 years ago

Help!! i dont understand this thanks if you helped :)

Nezavi [6.7K]

Answer:

28

Step-by-step explanation:

6 0

3 years ago

6. What is 30% of 70? Show your work.

o-na [289]

It is 23.3 percent thats correct

3 0

3 years ago