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STALIN [3.7K]
3 years ago
13

What is the responsible estimate of 6207 divided 214

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0

Answer:

31

Step-by-step explanation:

We want to estimate 6207 / 214

Round 6207 to 6200

and 214 to 200

6200/200

62/2 = 31

We know that our estimate will be a little high since we are rounding the denominator down

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In the diagram, the dashed figure is the image of the solid figure.
NISA [10]

Answer:

the answer is A because it is ap

3 0
3 years ago
In geometric progression, the ratio of each number to the preceding one is the same. Which is an example of a geometric progress
devlian [24]
It would be A because this sequence has a factor of 2 between each number
7 0
3 years ago
Read 2 more answers
A fish tank, shaped as a cube, has a volume of 36 liters, or 2,197 in cubed. What are the dimensions of the fish tank in Inches?
lutik1710 [3]

Answer:

l x w x h = 2,197

If l=w=h then it is a perfect cube.

The cube root of 2,197 is 13

Therefore, the cube is 13 x 13 x 13 inches.

Step-by-step explanation:

8 0
3 years ago
If X and Y are independent continuous positive random
Leni [432]

a) Z=\frac XY has CDF

F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy

where the last equality follows from independence of X,Y. In terms of the distribution and density functions of X,Y, this is

F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy

Then the density is obtained by differentiating with respect to z,

f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy

b) Z=XY can be computed in the same way; it has CDF

F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Differentiating gives the associated PDF,

f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Assuming X\sim\mathrm{Exp}(\lambda_x) and Y\sim\mathrm{Exp}(\lambda_y), we have

f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}

and

f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0
3 years ago
If an object is dropped from a height of 178 feet, the function h(t)=-16t^2+178 gives the height of the object after t seconds.
svp [43]

Answer:

B. 3.34s

Step-by-step explanation:

Find t when the object hit the ground, h(t)=0.

h(t)=-16t²+178

0=-16t²+178

16t²=178

t²=11.125

t=√11.125=3.33541601603s

4 0
3 years ago
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