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Amanda [17]
3 years ago
5

Plss helppp some math

Mathematics
2 answers:
elena-s [515]3 years ago
8 0

Answer:

9x² - 12x + 4

Division Property

Step-by-step explanation:

(3x-2)² = (3x-2)(3x-2)

using the foil method we get:

9x² - 6x - 6x + 4

combine 'like' terms to get:

9x² - 12x + 4

2x = 10  To get 'x' by itself, since it's being multiplied by 2 we must do the inverse operation which is division

If we divide one side of an equation by 2 we must do the same to the other side, giving us:

x = 10/2 which is x = 5

vodka [1.7K]3 years ago
3 0

Answer:

<h3>Question 5 : </h3>

9x^{2}  - 12x + 4

<h3>Question 6 :</h3>

Division property: divide both sides by 2

Step-by-step explanation:

<h3>Question 5 :</h3>

(3x - 2) ^{2}

(3x - 2)(3x - 2)

3x(3x−2)−2(3x−2)

3x(3x)+3x(−2)−2(3x−2)

{9x}^{2}  - 6x - 6x + 4

9x^{2}  - 12x + 4

<h3>Question 6 :</h3>

2x = 10

<h3>\frac{2x}{2}  =  \frac{10}{2}</h3><h3>x =  \frac{10}{2}</h3>

x = 5

<h3>Hope it is helpful....</h3>
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Brielle and Joshua are running a half marathon race, which is 13.1 miles long. It
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Answer:Brielle will run the half marathon race faster.Brielle will take 1 hour 44 minutes and 48 seconds, Joshua will take 2 hours 37 minutes and 12 seconds

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Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
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By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

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